JEE MAIN - Physics (2021 - 24th February Morning Shift - No. 19)
An unpolarised light beam is incident on the polarizer of a polarization experiment and the intensity of light beam emerging from the analyzer is measured as 100 Lumens. Now, if the analyzer is rotated around the horizontal axis (direction of light) by 30$$^\circ$$ in clockwise direction, the intensity of emerging light will be _________ Lumens.
إجابة
75
توضيح
Given, I0 = 100 lumens
When analyser is rotated through an angle $$\theta$$, the intensity of light will becomes
I = I0 cos2$$\theta$$ = 100 $$\times$$ cos230$$^\circ$$
= 100 $$\times$$ $${\left( {{{\sqrt 3 } \over 2}} \right)^2}$$ = 75 lumens
When analyser is rotated through an angle $$\theta$$, the intensity of light will becomes
I = I0 cos2$$\theta$$ = 100 $$\times$$ cos230$$^\circ$$
= 100 $$\times$$ $${\left( {{{\sqrt 3 } \over 2}} \right)^2}$$ = 75 lumens